5+[1+2(2x-3)]=6(x+5)

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Solution for 5+[1+2(2x-3)]=6(x+5) equation:


Simplifying
5 + [1 + 2(2x + -3)] = 6(x + 5)

Reorder the terms:
5 + [1 + 2(-3 + 2x)] = 6(x + 5)
5 + [1 + (-3 * 2 + 2x * 2)] = 6(x + 5)
5 + [1 + (-6 + 4x)] = 6(x + 5)

Combine like terms: 1 + -6 = -5
5 + [-5 + 4x] = 6(x + 5)

Remove brackets around [-5 + 4x]
5 + -5 + 4x = 6(x + 5)

Combine like terms: 5 + -5 = 0
0 + 4x = 6(x + 5)
4x = 6(x + 5)

Reorder the terms:
4x = 6(5 + x)
4x = (5 * 6 + x * 6)
4x = (30 + 6x)

Solving
4x = 30 + 6x

Solving for variable 'x'.

Move all terms containing x to the left, all other terms to the right.

Add '-6x' to each side of the equation.
4x + -6x = 30 + 6x + -6x

Combine like terms: 4x + -6x = -2x
-2x = 30 + 6x + -6x

Combine like terms: 6x + -6x = 0
-2x = 30 + 0
-2x = 30

Divide each side by '-2'.
x = -15

Simplifying
x = -15

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